Q: 我想整一條if
F4=44
我想整 F4 細過或等於40時 就出現個 差 字 F4係40-50個數值內就出現 一般 字 F4係 50或者以上既數值就出現 好 字
想問點整?
我想問如果"差" 果個字要紅色
同埋要計差同一般加埋係有幾多個,用邊個函數去計??有冇得比式/_\'..thankyou
A:
G4 =IF(F4<=40,"差",IF(F4>=50,"好","一般"))
G11 =COUNTIF(G4:G8, "差")
星期四, 4月 21, 2011
44.The sum of 3 consecutive EVEN number is 90. Find the smallest one.
Let x be the smallest consecutive EVEN number.
x + (x + 2) + (x + 4) = 90
=> 3x + 6 = 90
=> x + 2 = 30
=> x = 28
45.The sum of two numbers is 84 . If the large number exceed 3 times the smaller by 4 ,what is the larger number?
Let x be the smaller number and y be the larger number.
x + y = 84 --- (1)
3x + 4 = y --- (2)
Put (2) into (1):
x + (3x + 4) = 84
4x + 4 = 84
x = 20 --- (3)
Put (3) back into (2):
3(20) + 4 = y
y = 64
i.e. The larger number is 64.
46. Betty is 5kg lighter than twice the weight of Jane. Their total weight is 94kg. Find the weight of Betty.
Let x be the weight of Betty and y be the weight of Jane.
x + y = 94 --(1)
x + 5 = 2y --(2)
(1)-(2):
x + y - x - 5 = 94 - 2y
y - 5 = 94 - 2y
3y = 99
y = 33 --(3)
Put (3) back into (1):
x + 33 = 94
x = 61
i.e. the weight of Betty is 61 kg
47. There are some $2 coins and some $5 coins. The total value is $78 and the total number of coins is 21 . Find the number of $5 coins.
Let b be number of $2 coins and e be number of $5 coins.
2b + 5e = 78 --(1)
b + e = 21 --(2)
(1) - 2 x (2):
2b + 5e - 2b - 2e = 78 - 2 x 21
3e = 36
e = 12
i.e. the number of $5 coins is 12.
48. There are some $2 coins and some $5 coins. The total value is $169 and the total number of coins is 50 . Find the number of $2 coins
Let b be number of $2 coins and e be number of $5 coins.
2b + 5e = 169 --(1)
b + e = 50 --(2)
(1)- 5 x (2):
2b + 5e - 5b - 5e = 169 - 250
81 = 3b
b = 27
i.e. the number of $2 coins is 27
Let x be the smallest consecutive EVEN number.
x + (x + 2) + (x + 4) = 90
=> 3x + 6 = 90
=> x + 2 = 30
=> x = 28
45.The sum of two numbers is 84 . If the large number exceed 3 times the smaller by 4 ,what is the larger number?
Let x be the smaller number and y be the larger number.
x + y = 84 --- (1)
3x + 4 = y --- (2)
Put (2) into (1):
x + (3x + 4) = 84
4x + 4 = 84
x = 20 --- (3)
Put (3) back into (2):
3(20) + 4 = y
y = 64
i.e. The larger number is 64.
46. Betty is 5kg lighter than twice the weight of Jane. Their total weight is 94kg. Find the weight of Betty.
Let x be the weight of Betty and y be the weight of Jane.
x + y = 94 --(1)
x + 5 = 2y --(2)
(1)-(2):
x + y - x - 5 = 94 - 2y
y - 5 = 94 - 2y
3y = 99
y = 33 --(3)
Put (3) back into (1):
x + 33 = 94
x = 61
i.e. the weight of Betty is 61 kg
47. There are some $2 coins and some $5 coins. The total value is $78 and the total number of coins is 21 . Find the number of $5 coins.
Let b be number of $2 coins and e be number of $5 coins.
2b + 5e = 78 --(1)
b + e = 21 --(2)
(1) - 2 x (2):
2b + 5e - 2b - 2e = 78 - 2 x 21
3e = 36
e = 12
i.e. the number of $5 coins is 12.
48. There are some $2 coins and some $5 coins. The total value is $169 and the total number of coins is 50 . Find the number of $2 coins
Let b be number of $2 coins and e be number of $5 coins.
2b + 5e = 169 --(1)
b + e = 50 --(2)
(1)- 5 x (2):
2b + 5e - 5b - 5e = 169 - 250
81 = 3b
b = 27
i.e. the number of $2 coins is 27